y^2+8y-9=(y+9)(y-0)

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Solution for y^2+8y-9=(y+9)(y-0) equation: 



y^2+8y-9=(y+9)(y-0)

We move all terms to the left:

y^2+8y-9-((y+9)(y-0))=0

We add all the numbers together, and all the variables

y^2+8y-((y+9)(+y))-9=0

We multiply parentheses ..

y^2-((+y^2+9y))+8y-9=0



We calculate terms in parentheses: -((+y^2+9y)), so:

(+y^2+9y)

We get rid of parentheses

y^2+9y

Back to the equation:

-(y^2+9y)



We add all the numbers together, and all the variables

y^2+8y-(y^2+9y)-9=0

We get rid of parentheses

y^2-y^2+8y-9y-9=0

We add all the numbers together, and all the variables

-1y-9=0

We move all terms containing y to the left, all other terms to the right

-y=9

y=9/-1

y=-9

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